algebra math question??? help?

Question: 1. x^2+6x+9=0 2. x^2+ 2x-35=0 3.x^2-12x=-36 4. -x^2-4x=3 5.x^2-15-x= -54 6. -x^2+14x=48

Answer: Presume your problem is to factor and solve for x??? Look for factors of 9 which, when added together, are 6 (x + 3)(x + 3) = 0 x = -3, -3 2. Look for factors of - 35 which, when added together, are 2 (x + 7)(x - 5) = 0 x = -7, 5 3. Rewrite as x^2 - 12x + 36 = 0 Factors of 36 which when added together are - 12 (x - 6)(x - 6) = 0 x = 6, 6 4. Since working with positive numbers, to some, is "easier" multiply all terms by -1 x^2 + 4x + 3 = 0 Factors of 3 when added together are 4 (x + 3)(x + 1) = 0 x = -3, -1 5. x^2 - 15x + 54 = 0 Factors of 54 when added together are -15 (x - 9)(x - 6) = 0 x = 9; x = 6 6. x^2 - 14x + 48 = 0 2, 24 4, 12 6, 8 (x - 6)(x - 8) = 0 x = 6; x = 8

Related Questions

Related Items